It isn't actually used in printf; there's one more argument than there are %c sp... | Hacker News

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		JoshTriplett on June 23, 2015 \| parent \| context \| favorite \| on: C Puzzles It isn't actually used in printf; there's one more argument than there are %c specifiers. gcc -Wall warns about that.

brown-dragon on June 23, 2015 [–]

Good catch! And even if we do add another "%c" to fix it, I don't know why we would need to null-terminate a null-terminated string.

JoshTriplett on June 23, 2015 | [–]

If you added another %c, it would print the NUL to stdout; it doesn't terminate anything.

brown-dragon on June 24, 2015 | | [–]

You're right. My mistake.

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