I think your `n \* (n-1) / 2 + n` should be `n(n+1)(2n+1)/6` according to the SO...

		zimpenfish on Nov 1, 2023 \| parent \| context \| favorite \| on: Rob Pike’s Rules of Programming (1989) I think your `n * (n-1) / 2 + n` should be `n(n+1)(2n+1)/6` according to the SO article. `n * (n-1) / 2 + n` would be the sum of numbers, not sum of squares.

Thank you for the correction!