"Therefore, P is not equal to NP, is true and provable in a simply consistent extension B" of B"
does not necessarily imply P \neq NP (the caveat being the B" and B stuff). I'm not really a complexity theory guy, but I would say WHP that this either
(a) does not apply to the most general forms of computation (e.g., what people mean when they ask P =? NP)
edit: He appears to be a professor at Uppsala University in sweden: http://user.it.uu.se/~stenake/ .