Why am I not surprised that the PERL part could be solved with bash in the same ...

esaym · on Oct 24, 2020

Feel free to demonstrate. Take a long path with nasty characters and give me the ending file name. I want "track1.mp3" returned from:

  /podcast/with/nasty'--c h a r$/and/stuff/track1.mp3

zimpenfish · on Oct 24, 2020

If you have that in a variable, which you presumably would if you're reading them one at a time, you can use "remove longest matching prefix" substitution.

    $ i="/podcast/with/nasty'--c h a r$/and/stuff/track1.mp3"
    $ echo "${i##*/}"
    track1.mp3

[Edit: 'thezilch beat me too it by a couple of minutes]

sergeykish · on Oct 24, 2020

This part is really cryptic, I would prefer

    $ function remove_longest_matching_prefix () { echo "${1##$2}"; }
    $ remove_longest_matching_prefix "$i" '*/'
    track1.mp3

awk -F/ accepts stream as in perl example

Jare · on Oct 24, 2020

You still get +1 for providing a pointer to the explanation while remaining clear and succinct.

AareyBaba · on Oct 24, 2020

$ basename "/podcast/with/nasty'--c h a r$/and/stuff/track1.mp3"

track1.mp3

thezilch · on Oct 24, 2020

  $ path="/podcast/with/nasty'--c h a r$/and/stuff/track1.mp3"
  $ echo "${path##*/}"
  track1.mp3
  $ basename "${path}"
  track1.mp3
  $ echo "${path}" | awk -F/ '{print $NF}'
  track1.mp3

ubercow13 · on Oct 24, 2020

In zsh it would be

    echo “${uglypath:t}”