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Uhh, 20db isn't the same as 20s/n ratio though?


SNR = 10log(Ps/Pw), solving

Ps/Pw = 10^(SNR/10) = 10^(20/10) == 100

A signal 20db above the noise, you could put your eye out with it.

db is confusing, when you're talking voltage it's 20log(Vs/Vw) And in absolute terms engineers talk about the power over 1mW.

Myself I get miffed a bit because people have been conditioned to think in terms of trying to pull facts out of crappy data sets using poorly thought out statistics. However in a lot of engineering and physics fields the data is often really good. Often good enough that you can work off a single measurement.




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